(y^4+9y^2+20)/(y^2+4)

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Solution for (y^4+9y^2+20)/(y^2+4) equation: 


D( y )

y^2+4 = 0

y^2+4 = 0

y^2+4 = 0

1*y^2 = -4 // : 1

y^2 = -4

y in (-oo:+oo)

(y^4+9*y^2+20)/(y^2+4) = 0

(y^4+9*y^2+20)/(y^2+4) = 0 // * y^2+4

y^4+9*y^2+20 = 0

t_1 = y^2

1*t_1^2+9*t_1^1+20 = 0

t_1^2+9*t_1+20 = 0

DELTA = 9^2-(1*4*20)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)-9)/(1*2) or t_1 = (-1^(1/2)-9)/(1*2)

t_1 = -4 or t_1 = -5

t_1 = -5

y^2+5 = 0

1*y^2 = -5 // : 1

y^2 = -5

t_1 = -4

y^2+4 = 0

1*y^2 = -4 // : 1

y^2 = -4

y belongs to the empty set

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